Solved Problem on Clausius Inequality: Second Law and Entropy - Engineering Thermodynamics
SOLVED PROBLEM ON CLAUSIUS INEQUALITY
Problem 2.11
An inventor claims that his new engine will develop 30 kW for a heat addition of 2400 kJ/min. The highest and the lowest temperature of the cycle are 2200°C and 327°C respectively. Would you agree his claim? Use Clausius inequality method.
Given data:
W = 30 kW = 30 × 60 = 1800 kJ/min
Q1 = 2400 kJ/min
T1 = 1527°C = 2200 + 273 = 2473 K
T2 = 327°C = 327 + 273 = 600 K
To find:
Agreement his claim.
Solution:
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