Current (amp) drawn by an Electrical Equipment

let's just say I have a tank of 1000 ltr. and I put a hole in it at the bottom and fit a valve to control the flow of let's just say water.

Now let's say the level of water in the tank is voltage, the position of valve is resistance, the flow of water through valve is current, and last the size of valve is load.

Now if I open the valve completely, depending upon the level of water in the tank, the water will flow through valve. Higher the level of water in the tank the more water with high pressure is going to flow and vice versa I.e. Higher the level of water (voltage ) more the water (current) will flow ie. Current is directly proportional to the voltage.

Now let's talk about the resistance. The position of the valve is resistance right? if you completely open the valve water with high pressure will be flowing ( ie very low resistance) and as I keep on closing the valve the pressure will go on decreasing (more the resistance less is the flow of current). Ie. Current is inversely proportional to the resistance

Btw that is the ohms law: in a given close circuit current is directly proportional to voltage and inversely proportional to the resistance.

And the last thing is the size of the valve( ie size of the load) now if I remove the existing valve, drill the bigger hole and fit a bigger valve then existing one what is going to happen? Simple more water is going to flow. right? That means if we connect high rating equipments they are going to draw more current then the lower rated equipments.

So the current (amp) drawn by an electrical equipment will depend upon the given voltage, total resistance in the circuit, and the rating of an equipment.